Apollonius' theorem states that the mean of the areas of the squares on any two sides of any triangle equals the sum of the area of the square on half the third side and the area of the square of the median bisecting the third side... See below:
Pepe Chapuzas proved the theorem:
Dear Teacher:
The cosine law states that
a2 = m2 + c2/4 − m · c · cos θ
b2 = m2 + c2/4 − m · c · cos θ' = m2 + c2/4 + m · c · cos θ
(θ and θ' are suplementary)
So, the mean of a2 and b2 is
(a2 + b2) / 2 = m2 + c2/4
Mr. López, when the triangle is isosceles, Apollonius' theorem becomes Pithagoras' theorem, doesn't it?
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